0=x^2-420x-8000

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Solution for 0=x^2-420x-8000 equation:



0=x^2-420x-8000
We move all terms to the left:
0-(x^2-420x-8000)=0
We add all the numbers together, and all the variables
-(x^2-420x-8000)=0
We get rid of parentheses
-x^2+420x+8000=0
We add all the numbers together, and all the variables
-1x^2+420x+8000=0
a = -1; b = 420; c = +8000;
Δ = b2-4ac
Δ = 4202-4·(-1)·8000
Δ = 208400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{208400}=\sqrt{400*521}=\sqrt{400}*\sqrt{521}=20\sqrt{521}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(420)-20\sqrt{521}}{2*-1}=\frac{-420-20\sqrt{521}}{-2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(420)+20\sqrt{521}}{2*-1}=\frac{-420+20\sqrt{521}}{-2} $

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